抄写例题作业1

截图

1.例9.1

（1）代码实现

#include<stdio.h>
int main()
{
    struct stu
    {
        long int num;
        char name[20];
        char sex[3];
        char addr[20];
    }a={1010,"董诗原","男","hkj"};
    printf("No:%d\nname:%s\nsex:%s\naddr:%s",a.num,a.name,a.sex,a.addr);
 } 

（2）运行结果

No:1010
name:董诗原
sex:男
addr:hkj
--------------------------------
Process exited after 0.4101 seconds with return value 0
请按任意键继续. . .

2.例9.2

（1）代码实现

#include<stdio.h>
int main()
{
    struct stu
    {
        long int num;
        char name[20];
        float score;
    }stu1,stu2;
    scanf("%d%s%f",&stu1.num,stu1.name,&stu1.score);
    scanf("%d%s%f",&stu2.num,stu2.name,&stu2.score);
    printf("The higher score is:\n");
    if(stu1.score>stu2.score)
    printf("%d %s %.2f\n",stu1.num,stu1.name,stu1.score);
    else if(stu1.score<stu2.score)
    printf("%d %s %.2f\n",stu2.num,stu2.name,stu2.score);
    else{
        printf("%d %s %.2f\n",stu1.num,stu1.name,stu1.score);
        printf("%d %s %.2f\n",stu2.num,stu2.name,stu2.score);
    }
 } 

（2）运行结果

10101 wang 89
10103 ling 90
The higher score is:
10103 ling 90.00--------------------------------
Process exited after 25.17 seconds with return value 0
请按任意键继续. . .

3.例9.3

（1）代码实现

#include<stdio.h>
#include<string.h>
int main()
{
    struct per{
        char name[20];
        int count;
    }a[3]={"li",0,"zhang",0,"sun",0};
    char b[20];
    for(int i=0;i<10;i++)
    {
        scanf("%s",&b);
        if(strcmp(b,a[0].name)==0)
        a[0].count++;
        else if(strcmp(b,a[1].name)==0)
        a[1].count++;
        else
        a[2].count++;
    }
    printf("\nResult:\nli:%d\nzhang:%d\nsun:%d\n",a[0].count,a[1].count,a[2].count);
 } 

（2）运行结果

li
li
sun
zhang
zhang
sun
li
sun
zhang
liResult:
li:4
zhang:3
sun:3--------------------------------
Process exited after 55.91 seconds with return value 0
请按任意键继续. . .

4.例9.4

（1）代码实现

#include<stdio.h>
struct stu
{
    long int num;
    char name[20];
    float score;
};
int main()
{
    struct stu t;
    struct stu s[5]={10101,"zhang",78,10103,"wang",98.5,10106,"li",86,10108,"ling",73.5,10100,"sun",100 };
    for(int i=0;i<5;i++){
        for(int j=1;j<5-i;j++)
        {
            if(s[j].score>s[j-1].score)
            {
                t=s[j];
                s[j]=s[j-1];
                s[j-1]=t;
            }
        }
    }
    for(int i=0;i<5;i++)
    {
        printf("%d%8s%8.2f\n",s[i].num,s[i].name,s[i].score); 
    }
}

（2）运行结果

10100     sun  100.00
10103    wang   98.50
10106      li   86.00
10101   zhang   78.00
10108    ling   73.50--------------------------------
Process exited after 0.46 seconds with return value 0
请按任意键继续. . .

5.例9.5

（1）代码实现

#include<stdio.h>
#include<string.h>
int main()
{
    struct stu
    {
        long int num;
        char name[20];
        char sex;
        float score;
    };
    struct stu stu_1;
    struct stu *p;
    p=&stu_1;
    strcpy(stu_1.name,"Li lin");
    stu_1.num=10101;
    stu_1.sex='M';
    stu_1.score=89.5;
    printf("No:%d\nname:%s\nsex:%c\nscore:%.2f\n\n",stu_1.num,stu_1.name,stu_1.sex,stu_1.score);
    printf("No:%d\nname:%s\nsex:%c\nscore:%.2f",(*p).num,(*p).name,(*p).sex,(*p).score);
}

（2）运行结果

No:10101
name:Li lin
sex:M
score:89.50No:10101
name:Li lin
sex:M
score:89.50
--------------------------------
Process exited after 0.4481 seconds with return value 0
请按任意键继续. . .

6.例9.6

（1）代码实现

#include<stdio.h>
#include<string.h>
struct stu
{
    long int num;
    char name[20];
    char sex;
    int age;
};
struct stu a[3]{10101,"Li lin",'M',18,10102,"Zhang fang",'M',19,10104,"Wang min",'F',20};
int main()
{
    struct stu *p;
    printf(" No.        name     sex    age\n");
    for(p=a;p<a+3;p++)
    printf("%5d%13s%5c%7d\n",p->num,p->name,p->sex,p->age);
}

（2）运行结果

 No.        name     sex    age
10101       Li lin    M     18
10102   Zhang fang    M     19
10104     Wang min    F     20--------------------------------
Process exited after 0.1007 seconds with return value 0
请按任意键继续. . .

7.例9.7

（1）代码实现

#include<stdio.h>
#include<string.h>
struct stu
{
    long int num;
    char name[20];
    float score[3];
    float aver;
};
struct stu a[3];
int main()
{
    printf("请输入各学生信息：学号，姓名，三门课成绩：\n");
    for(int i=0;i<3;i++)
    {
        a[i].aver=0;
        scanf("%d%s",&a[i].num,a[i].name);
        for(int j=0;j<3;j++)
        {
            scanf("%f",&a[i].score[j]);
            a[i].aver=a[i].aver+a[i].score[j];
        }
        a[i].aver/=3;
    }
    int max=a[0].aver;
    int count;
    for(int i=1;i<3;i++)
    {
        if(a[i].aver>max){
            max=a[i].aver;
            count=i;
        }
    }
    printf("\n成绩最高的学生是：\n");
    printf("学号：%d\n姓名：%s\n",a[count].num,a[count].name);
    printf("三门课成绩: ");
    for(int i=0;i<3;i++)
    printf("%.1f ",a[count].score[i]);
    printf("\n平均成绩：%.2f",a[count].aver);
}

（2）运行结果

请输入各学生信息：学号，姓名，三门课成绩：
10101 li 78 89 98
10103 wang 98.5 87 69
10106 sun 88 76.5 89成绩最高的学生是：
学号：10101
姓名：li
三门课成绩: 78.0 89.0 98.0
平均成绩：88.33
--------------------------------
Process exited after 64.47 seconds with return value 0
请按任意键继续. . .